Click here 👆 to get an answer to your question ️ 3x5/2x1 = 1/3 give the solutionView Math 1440 Test 2 Sample Questionspdf from MATH 1440 at University of Iowa Sample Test 2 Questions Set 1 1 If y = 2x−1 3x4 , 2 If y = x x−5 , 3 If 5 x −1 3 what is the inverse of y?Click here👆to get an answer to your question ️ Solve 2x 3≥ 5 Solve Study Textbooks Guides Join / Login >> Class 11 >> Applied Mathematics >> Functions >> Introduction of functions >>
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3-5(-3x+1)+8x=-2x+5
3-5(-3x+1)+8x=-2x+5-Math Precalculus Precalculus questions and answers 1 A) Is the function below, continuous as x tends to 5?24/7 help from Expert Tutors on 140 subjects;
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Full access to over 1 million Textbook SolutionsThe relative maximum is about (3,41), and the relative minimum is about (2,22) Divide 3x^33x^22x2 by x3 using long division Divide using sythetic division Miguel is designingGet more out of your subscription* Access to over 100 million coursespecific study resources;
Answer 2x−5 = 3x2 2x−1 cross multiplication (2x−5) (3x2)= (3x−1) (2x−1) 2x (3x2)−5 (3x2)=3x (2x−1)−1 (2x−1) 6xX = −3 Explanation 3(x 5) = 2(3x12) or 3⋅ x 15 = 6⋅x 24 or 3⋅x −6⋅ x = 24− 15 or − 3⋅x = 9 2x93xx=1x5 One solution was found x = 4/5 = 0800 Rearrange Rearrange the equation Stepbystep explanation −3x 5 (−8x −1) First, distribute 5 into the parenthesis = −3x 5 (−8x −1) = 3x 40x 5 Combine like terms = 43x 5 Advertisement
6x2 13x− 5 Explanation (3x −1)(2x5) = 3x(2x 5)−1(2x 5) 3x3=x5 One solution was found x = 4 Rearrange Rearrange the equation by subtracting what is to the right of the equal signB D = −12;∞;F (x) = { 2x − 6 x < 5 = {x2 − 3x x ≥ 5 B) By trial and error, determine one value of x at
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Stepbystep explanation 3 (x 3) 8x = 5 (2x 1) FOIL 3x 9 8x = 10x 5 Move all the x terms to one side and all the constants to the other 3x 8x 10x = 5 9Simplify (2x1) (3x5) (2x 1) (3x − 5) ( 2 x 1) ( 3 x 5) Expand (2x1)(3x− 5) ( 2 x 1) ( 3 x 5) using the FOIL Method Tap for more steps 2x(3x)2x⋅−51(3x) 1⋅−5 2 x ( 3 x) 2 x ⋅ 5Given inequation, 3 x / 5 – (2 x – 1) / 3 > 1 (9 x – 1 0 x 5) / 1 5 > 1 Taking LCM − x 5 > 1 5 − x > 1 5 – 5 − x > 1 0 x < − 1 0 As x ∈ R Hence, the solution set is x x ∈ R, x < − 1 0 Representing
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